3x+4(4x+x^2+1)-4(1+5x)-4x^2=8

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Solution for 3x+4(4x+x^2+1)-4(1+5x)-4x^2=8 equation: 


Simplifying
3x + 4(4x + x2 + 1) + -4(1 + 5x) + -4x2 = 8

Reorder the terms:
3x + 4(1 + 4x + x2) + -4(1 + 5x) + -4x2 = 8
3x + (1 * 4 + 4x * 4 + x2 * 4) + -4(1 + 5x) + -4x2 = 8
3x + (4 + 16x + 4x2) + -4(1 + 5x) + -4x2 = 8
3x + 4 + 16x + 4x2 + (1 * -4 + 5x * -4) + -4x2 = 8
3x + 4 + 16x + 4x2 + (-4 + -20x) + -4x2 = 8

Reorder the terms:
4 + -4 + 3x + 16x + -20x + 4x2 + -4x2 = 8

Combine like terms: 4 + -4 = 0
0 + 3x + 16x + -20x + 4x2 + -4x2 = 8
3x + 16x + -20x + 4x2 + -4x2 = 8

Combine like terms: 3x + 16x = 19x
19x + -20x + 4x2 + -4x2 = 8

Combine like terms: 19x + -20x = -1x
-1x + 4x2 + -4x2 = 8

Combine like terms: 4x2 + -4x2 = 0
-1x + 0 = 8
-1x = 8

Solving
-1x = 8

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '-1'.
x = -8

Simplifying
x = -8

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